models: break out of loops#12159
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will an empty case not result in the same result but not require a goto and lable? |
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the error came from when during a failed refactor attempt I tried to move this out to a method that returned directly - but didn't I unwind the refactor completely |
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Maybe break could be replaced with |
lunny
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Jul 6, 2020
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make lgtm work |
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Jul 31, 2020
Co-authored-by: Lunny Xiao <xiaolunwen@gmail.com>
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This fixes three spots in the
modelspackage where abreakwas being called from aswitchthat was inside aforloop, turning it into a no-op. This labels the outer loop so thebreakwill make it out of both theforand theswitch.